Bank PO Exam Questions with Solution - Top Method

Bank PO Exam Questions with Answer

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Q. 1 The Length of Rectangle is three fifth of the side of a square. The radius of a circle is equal to side of the square. The circumference of the circle is 132 cm. What is the area of the rectangle if the breadth of the rectangle is 8cm ?

Solution

2∏r = 132

2 * 22/7 * r = 132

r  = (132 *7 )/( 2 * 22)  = 21 cm

side of square is = 21 cm

length of rectangle  = (3 * 21)/ 5 cm

so area of rectangle is = (3 * 21)/ 5 * 8 = 100.8 Sq. cm Ans.

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Q. 2 Five Fifth of a number is equal to twenty five percent of second number.  Second Number is equal to one fourth of third number. The value of third number is 2960. What is 30 % of the First number?

Solution

Second Number = ¼ * 2960 = 740

First number  * 5/9  = (740* 25)/100

So first number = 740/4 * 9/5  = 333

So 30% of 333  = (333* 30)/ 100  = 99.9 Ans.

Q. 3 The respective Ratio B/W present age of Manoj and Wasim is 3  :11. Wasim is 12 years younger than Rehana. Rehana’s age after 7 years will be 85 years. What is the present age of Manoj”s father who is 25 years older than manoj?

Solution

Rehana’s present age is  = 85 -7 = 78 years

Wasim’s present age is  = 78 – 12 = 66 years

Manoj’s present age is  = 3/11 * 66 = 18 years

Manoj’s father’s present age is   = 25 + 18  = 43 years ans.

Q. 4 Dinesh’s monthly icome is four times suresh’s monthly income. Suresh’s monthly income is 20 % more than joyti’s monthly income is Rs 22, 000. What is the dinesh’s monthly income?

Solution

Suresh’s monthly income  = ( 22000* 120)/100  = Rs 26400

So dinesh monthly income 

= ( 4 * 26400)  = Rs ( 105600) ans.

Q. 5 Smallest side of a right angled triangle is 8 cm less than the side of a squre of perimeter 56 cm. Second largest side of the right angled triangles is 4 cm less than the length of a rectangle of area 96 square cm and breadth 8 cm. What is the largest side of the right angled triangle?

Solution

Side of square = perimeter/4  = 56/4 = 14 cm

So smallest side of right angled  = 14 -8 = 6cm.

Length of rectangle  = area/breadth

                                   = 96/8  = 12 cm.

So second side of the triangle  = 12 -4 = 8cm

Then hypotenuse of the right angled triangle  = √ 6² + 8²

                                                                                     = √ 36 + 64

                                                                                  = √100  = 10cm ans.

Q. 6 The Ratio between the adjacent angles of a parallelogram is 7 : 8 respectively. Also the ratio between the angles of quadrilateral is 5 : 6: 7 : 12. What is the sum of the smaller angle of parallelogram and second largest angle of quadrilateral?

Solution 

Let the adjacent angles be 7x degree and 8 x degree

Then 7 x + 8 x = 180

=>   15x = 80

=>    x = 12

So that smaller angle  = 7 * 12  = 84 degree

Again 5y + 6y + 7y + 12y = 360 degree

30y = 360 degree

Y = 360/30  = 12 degree

Then second largest angle of the quadrilateral  = 7 * 12 = 84 degree

Required sum  = 84 + 84  = 168 degree Ans.

Q. 7  Raju runs 1250 metre on Monday and Friday. Other days he runs 1500 meters except for Sunday. How many kilometers will he run in 3 weeks ( first day starting from Monday)?

Solution

Total distance covered is = 3 ( 2 * 1250 + 4 *1500) metre

                                              =  3 ( 2500 + 6000) metre

                                               25500 metre   = 25.5 km Ans.

Q. 8 The sum of consecutive odd numbers of set – A is 621. What is the sum of different set of six consecutive even numbers whose lowest number is 15 more than the lowest number of set – A ?

Solution

Fifth number of set A  = 621/9  = 69

Smallest number of Set A  = 61

Then smallest number of set B  = 61 + 15  = 76

Required sum  = 76 + 78 + 80 + 84 + 86  = 486 ans.

Q. 9 In a school there are 250 students out of whom 12 percent are girls. Each girls monthly fee is Rs 450 and each boy’s monthly fee is 24% more than a girl. What is the total monthly fee of girls and boys together?

Solution

Monthly fee of each boy is  =( 450 * 124 )/100  = Rs 558

Number of girls  = (250 *12)/100  = 30

Number of boys  = Rs 220

Total monthly fee  = Rs ( 220 * 558 + 30 * 450)

                          = ( 122760 + 13500)  = 136260 Rs ans

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Q. 10 The average speed of a train is 1^3/7 times the average speed of a car. The car covers a distance of 588 km in 6 hours. How much distance will the train cover in 13 hours?

Solution

Average speed of car  = distance/time  = 588/6  = 98kmph

Average speed of train is  = (98 * 10 )/7  = 140 kmph

Distance covered by train in 13 hours  = speed * time

                                                                      = 140 * 13  = 1820 Km.

Q. ( 11 – 15) What will come in place of x in the following questions?

Q. 11 (21)²  - 3717 ÷ 59 = x * 8

Solution

(21)²  - 3717 ÷ 59 = x * 8

441 – 3717/59  = 8x

441 – 63 = 8x

X =  378/8

  = 47.25 Ans.

Q. 12 2 ¹/8  - 1 ¹/17 = x + 1 ¹/ 32 – 1⁹/64

Solution

X = 2 – 1 – 1 + 1 + ( 1/8 + 1/16 – 1/32 + 9/64)

X = 1 + 11/64 = 1 ^11/64 Ans.

Q. 13 ( 0.64)⁴ ÷ (0. 512)³ * (0.8)⁴ = (0.8)^{x + 3}

Solution

((0.8)²)⁴  ÷ ( 0.8³)³  * (0.8)⁴   =  (0.8)^x+3

(0.8)^{8 -9 +4}   = (0.8)^x+3

X + 3  = 3

X = 0 Ans.

Q. 14 34.5 % of 1800 + 12.4 % of 1500 = (x)³ + 78

Solution

(1800 * 34.5)/ 100  +  (1500 * 12.4)/100   =   (x)³ + 78

621 + 186  = (x)³ + 78

(x)³  =   807 – 78  = 729

X = 9 Ans.

Q. 15  √(15)² * 12 ÷ (9) – 125 + 21 = x

Solution

√ (225 * 12)/9  - 125 + 21

√ 300 – 125 + 21

√196 = 14 Ans.

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