Percentage: Quantitaive Aptitude Question Answers Short Tricks

Here Check Percentage Based questions with  Answers, Percentage Problems Short Tricks, Percentage Question with Solution, How to Solve Percentage Based questions easily,  How to Solve Percentage Problems in less time, Best Method to Solve Percentage Problems so please go through this blog and any other further information please stay connect our blogs.

Q 1. The Salary of Aman is 50% more than the salary of the Rahul then how much % of the salary of Rahul is less than the salary of Aman.

Solution  

If we want to calculate more % then direct calculate at formula =

More % - Less %  × 100 

Less Percentage

Less Percentage  = Less % - More %/More %*100

Then  

150 -100/150*100  = 50/15*10

= 100/3 = 331/3  Ans.

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Q. 2 If the Numerator of the fraction is increased by 50% and denominator is increase by 200 then fraction become 4/7 find the original fraction.

Solution

Let the Numerator is X and Denominator is Y then According to question

150X/300Y = 4/7

X/Y = 8/7ans.

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Q. 3 If the length of rectangle is increased by 40% and breadth decrease by 20% then the area of rectangle.

Solution

This type of question you can solve easily at

+ A  +B  +AB/100    

here  A is Length & B is Breadth

and + shows the Increment and – shows the decrement in length & breadth

Then + 40 – 20 -40*20/100

=        +20 – 8 = + 12 Ans.

Q. 4 Each Side of Square is increased by 13% then what will be effect on its area.

Solution

We solve it above given formula directly

+ 13 + 13 +  13*13/100

= 26 + 1.69 = 27.69 Ans.

Q. 5 in the exam 35 % students passed the exam and 455 students are failed the exam then find the number of students appeared in the exam.

Solution

Let total students sits in exam is 100 then 35% is passed so failed students is 65%

By short tricks

65% = 455

1% = 455/65

& 100 % is = 455/65* 100 = 700 Ans.

Q.6 The Price of Sugar reduced by 25% then a man can buy 4 Kg more sugar t 420 Rs then calculate

1. Reduced Price    2. Original Price

Solution

420 * 25/100 = 420 * ¼  = 105

Then 4 kg sugar’s price = 105

1kg sugar price is = 105/4 = 26.25 per/kg Ans

2. 75%  = 26.25

     1% = 26.25/75 * 100 = 35 per/kg Ans.

Q. 7  Rahul spends 20% of his income on food and its 50% spends on the rent of the remaining 30% spends on games. If the total saving is 6300 then find monthly income of Rahul.

Solution

Let total income is 100 then 100 – 20 = 80

Then 50 % of 80 is = 50 * 80/100 = 40

Then 80 – 40  = 40

Now 40 of 30% = 12

40 – 12 = 28%

If 28%  = 6300

1% = 6300/28

& 100% = 6300/28*100 = 22500

Q. 8 Rahul expenses 20% of his salary on food and 16% on rent and 12% on games if the savings is 52000 Rs find his monthly income.

Solution

Saving = Income – Exp

Total Expenditure is = 20 + 16 +12 = 48%

Remaining is = 100 – 48 = 52

Then 52% = 52000

          1%  = 52000/52

100% is = 52000/52*100 = 100000Ans.

Q. 9 In the election a candidates got 84% vote and won election by 476 votes then find total number of voters.

Solution

Candidates who won get votes = 84%

And loser get                              = 16%

Then winner won by 68% votes

68% = 476

1%   = 476/68

And 100% = 476/68 * 100 = 700

Q. 10 A students has to obtained 33% of the total marks to passed the exam he got 125 marks and failed by 40 marks then  find the max marks.

Solution

125 + 40 = 165

33% = 165

1 % = 165/33

And 100% = 165/33 * 100 = 500 Ans.