Time Speed & Distance Aptitude Questions with Solution - Best Method

Time Speed & Distance Problems with Solution

Here we will provide easiest method to solve time, speed & distance questions, How to Solve time, speed & distance questions easily, best method of solution time, speed & distance problems so please go through this blog and get beautiful information here.

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Q. 1 In covering a certain distance, the speeds of A & B are in the ratio 3 : 4,  A takes 30 minutes more than B to reach the destination. The Time Taken by A to reach the destination is?

Ratio of speeds  = 3: 4

Then ratio of time taken  = 4 : 3

Suppose a takes 4x hrs and B takes 3x hrs to reach destitaion, then

4x  - 3x  = 30/60  = ½ or  x= ½

Time taken by A  = 4 *1/2  = 2hrs ans.

Q. 2 A car covers a distance of 715 Km at a constant speed, if the speed of the car would have been 10 km/hr more, then it would have taken 2 hours less to cover the same distance. What is the original speed of the car is?

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Answer

Let the original speed be x km/hr then 715/x – 715/(x +10)  = 2

2x(x +10)  = 7150

X² +10x- 3575 = 0

X = 55  km/hr Ans.

Q. 3 Excluding stoppage, the speed of a bus is 54 kmph and including stoppages it is 45 Kmph, for how many minutes does the bus stop per hour ?

Answer

Due to stoppage it covers 9 km less

Then, taken to cover 9 km  = 9/54 * 60

Min  = 10 minute ans

Q. 4 A train can travel 50% faster than a car, Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way however, the train lost about 12.5 minutes while stopping the station. The speed of the car is?

Answer

Let the speed of car x kmph then speed of the train

= 150/100x  = 3/2 kmph

75/x – 75/3/2x  = 125/(10*60)

= 75/x – 50/x = 5/24

X  = ( 25*25)/5 = 120kmps Ans.

Q. 5 A car travel from P to Q at a constant speed. If its speed were increased by 10 Km/hr, it would have taken one hour less to cover the distance. It would have taken further 45 minutes lesser if the speed was further increased by 10 km/hr. what is the distance between the two cities?

Let distance = x km and usual rate y kmph,

Then x/y – x/(y+10) = 1 or

Y ( y+10)  = 10x

And x/y – x/(y+2o)  = 7/4

Or y (y + 20)  = 80/7 x

On dividing 1 by II we get y = 60

Substituting  y = 60 we get X  = 420 km Ans

Q. 6 A man covered a certain distance at some speed. Had he moved 3 Kmph fater would have taken 40 minutes less. If he had moved 2kmph slower, he would taken 40 minute more, the diatnce in Km is?

Answer

Let distance  = Km snd usual rate  = Y

X/y – X/ (Y+3)  = 40/60

Or  2Y ( Y+3)  = 9X

And X/(Y-2) – X/Y  = 40/60

Or Y ( Y-2)  -  3X

On dividing 1 by II we get  X  = 40 Km ans

Q. 7 If a trains runs at 40 kmph, it reaches its destination late by 11 minutes but if it runs at 50 kmph, it is late by 5 minutes only. The correct time for the train to its journey is?

Answer

Req. distance  = (T1 + T2)/60 * (S1S2)/(S2 – S1)

(11+5)/60 * (40*50)/(50 – 40)

Distance  = (16/60) * (40 * 50)/10  = 160/3km

Actual Time  = (160/3 * 40) – 11/60 =  4/3 – 11/60

ð  (80-11)/60  = 69/60 hr   = 69 min Ans

Q .8 Two men start together to walk to a certain destination, one at 3 kmph and another at 3.75 kmph. The latter arrives half an hour before the former. The distance is?

Answer

Let the distance be X km, then

X/3  - X/3.75  = ½

=>  2.5X – 2X = 3.75

X = 3.75/0.50  =  15/2  = 7.5 Km Ans.

Q. 9 A train when moves at an average speed of 40kmph, reaches its destination. When its average speed becomes 35 kmph, then it reaches its destination 15 late, find the distance of journey?

Answer

Difference between timing  = 15 min  = ¼ hr

Let the length of journey is X km

Then X/35  - X/40   = ¼

= 8X  - 7 X  = 70

X = 70 Km ans

Q. 10 Walking 6/7^th of his actual speed, a man is 12 minutes too late,  The actual time taken by him to cover that distance is?

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Answer

New speed  = 6/7 of usual speed

New time = 6/7 of usual time

(7/6 of usual time) – ( usual time)

= 1/5 hr  = 1/6 of usual time = 1/5 hr

Usual time = 6/5 hr  = 1 hr  12 min

Q. 11 A man can reach a certain place in 30 hrs. if he reduces his speed 1/15^th in 10 km less in that time, find his speed?

Answer

Let the speed is km/hr then

30X – 30 * 14/15X = 10

= > 2X = 10

X  = 5 km/hr  Ans

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