SBI PO Previous Year Solved Paper, SBI PO Sample Paper 2017

SBI PO Math Sample Paper 2017

Competitior who are looking for state bank of india PO exam 2017 sample papers here we are give Math sample paper for SBI PO Examination. Students can check here SBI PO exam Model Paperes, SBI PO Sample Papers PDF, SBI PO Prvious Year Papers PDF, SBI PO Examination Papers for math subjects.

Q. 1 On republic day sweets were to be equally distributed among 450 children. But on that particular day 150 children remained absent. Thus each got 3 sweets extra, how many sweets did child get?

Solution

Number of sweets for 150 absent children

= 300 * 3 = 900

Number of sweets each student gets = 900/150  + 3

                                                                   = 9 Ans.

SBI PO Vacancies 2017 - Click Here

Q. 2 In how many different ways can the letters of the word “trust” be arranged?

Solution

The word trust consists of five letters in which T comes twice

Number of arrangement = └5/ L2

= ( 5 * 4 * 3 * 2 * 1)/(2 *1)

= 60 Ans.

Latest Google Trends News - Click Here

Q. 3 Amit, Sucheta and neeti strat running around a circular track and complete one round in 18, 24 and 32 seconds respectively. In how many seconds will the three meet again at the starting point if they all started running at the same time?

Solution

Required time   = LCM of 18, 24 and 32

                            = 288 Seconds Ans.

Q. 4 A bsket contains three blue and four red balls. If three balls are drawn at random from the basket, what is the probability that all three are either blue or red?

Solution

Number of possible outcomes

N(s)  = 7c₃   = (7 *6 * 5)/(1 *2 *3)

= 35

Favorable number of cases

N (e) = 3c₃ + 4c₃

=          1 + 4 = 5

Required probability

N (e)/n (S)  = 5/35

= 1/7 ans.

Q. 5 A man buys a single apple for Rs 25. If he were to buy  a dozen apples, he would have to pay a total amount of Rs 250. What would be the approximate percent discount he would get on buying a dozen apples?

Solution

Required percentage = (50 *100)/ 300 = 17ans

Q. 6 6 men can complete a piece of work  in 12 days. 8 women can complete the same piece of work in 18 days wheres 18 childeren can complete the piece of work in 10 days. 4 men , 12 women and 20 chilkdren work together for 2 days. If only men were to complete the remaing work in 1 day how many men would be required totally.

'

Solution

72 men = 144 women = 180 childeren

2 men = 4 women = 5 children

4 men +12 women + 20 children

= 4 men + 6 Men + 8 Men = 18 men

When 6 men can complete a work in 12 days

18 men will do the same in 4 days

Then remaining work = ½

M1 D1/W1 = M2 D2/W2

= ½ * 6 * 12 = 1 * m2

M2 = 36 number of men

Q. 7 Percent Profit Earned six company’s over the years is given table

Company/Year	P	Q	R	S	T	U
2004	11	12	3	7	10	6
2005	9	10	5	8	12	6
2006	4	5	7	13	12	5
2007	7	6	8	14	14	7
2008	12	8	9	15	13	5
2009	14	12	11	15	14	8

(Q 8 -13) Study the above table carefully to answer the questions that given below

Q. 8 If the profit Earned by company R in the year 2008 Rs 18.9 lakhs, what was the income in that year?

Solution

If the expenditure be Rs X lacs then

18.9/x * 100  = 9

=> x = (18.9*100)/9

= 210 lakh

So income = Rs ( 210 + 18.9) lakh

Rs 228.9 lacs ans.

Q. 9 What is the percentage rise in percent profit of company T in year 2009 from the year 2004?

Solution

Percentage increase is

= 4/10 * 100

= 40% ans.

Q. 10 If the profit earned by company P in the year 2007 was Rs 2.1 lakhs, what was its expenditure in that year?

Solution

Required expenditure of the company

= (2.1 * 100)/7

= Rs 30 lacs Ans.

Q. 11 What was the average percent profit of company S over all the years together?

Solution

Average percent profit

= (7 + 8 + 13 + 14 + 15 + 15)/6

= 12% Ans.

Q. 12 What is the difference between the percent profit earned by company Q in the year 2005 and the average profit earned by the remaining companies together in that year?

Solution

Required difference   = 10 – ( {9+5 + 8 + 12 +6)/5})

10 – 8 = 2 % ans.